Mathematics, 06.06.2021 19:00 sophia4636
Solve dU/dt = d^2U/dx^2,0 < x < 6, t > 0, subject to the conditions U(0,t) = U(6,t)=0, U(x,0)=( 1 if 0<= x <= 3 & 0 if 3 <= x <= 6). Interpret physically.
Answers: 1
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Solve dU/dt = d^2U/dx^2,0 < x < 6, t > 0, subject to the conditions U(0,t) = U(6,t)=0, U(x,...
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