Sanjay uses the steps below to solve the equation 4 p + two-fifths (10 + 2 p) = 8. Step 1 Multiply both sides of the equation by Five-halves. 4 p + 10 + 2 p = 20 Step 2 Simplify like terms. 6 p + 10 = 20 Step 3 Subtract 10 on both sides of the equation. 6 p = 10 Step 4 Divide both sides of the equation by 6. p = StartFraction 10 over 6 EndFraction = Five-thirds = 1 and two-thirds Which is the first error that Sanjay made when finding the solution?

Step 1 Multiply both sides of the equation by Five-halves

Step-by-step explanation:

First mistake:

Step 1 Multiply both sides of the equation by Five-halves

Correct First step:

Should have subtracted 4p from both sides

idk

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)