Line A has a slope of 3/2 and passes through the point (3, 3). Line B has a slope of – 1/3 and passes through the point (-4, -2). At what point does line A intersect line B? Line Aintersects line B at the point ( , ).​

The lines meet at (-1, -3)

Step-by-step explanation:

Line A :

Line B :

Solve for x and y from the linear equation to find where line A and line B meets :

2y = 3x - 3 => 3x - 2y = 3 ------- (1)

3y = -x - 10 => -x = 3y + 10

                => x = - 3y - 10 --------(2)

Substitute (2) in (1) : => 3(- 3y - 10) - 2y = 3

                                   -9y - 30 -2y = 3

                                       -11y = 3 + 30

                                         -11y = 33

                                            y = -3

Substitute y in (2) : => x = -3 (-3) - 10 = 9 - 10 = -1

d. 145*2 is 290 than the total angle is 360 then minus 290 then divide by two

the area of a triangle is determined by the formula: base x height * 1/2

you'll need to assign a base to the triangle. based on the vertices given, the simplest base would be the line segment from (-2,1) to (2,1). the distance between any two numbers is found by just subtracting them. here, you should subtract the x values to find the distance of this side.

2 - (-2) = 4.

so the distance (aka the length of the base) is 4. the height of the triangle is the distance between the base and the highest point on the triangle which is (3,4). we should subtract the y values this time to find the height/distance.

4 - 1 = 3

so the height is 3.

base = 4

height = 3

hope this if needed hmu