Which shows a quadratic function?

OPTION B IS YOUR ANSWER.

You know its a quadratic when the second difference of each y value is same.

Here's what I mean.

Option B

First all x values differ by 1. So we're good on those.

Now for the y values

Which are

3, -1, -3, -3, -1

find the difference between the second and first fod each... Then do this a second time.

If it gives the same value for all the second differences... Then its quadratic.

-1-3 = -4

-3-(-1) = -3 + 1 = -2

-3-(-3) = -3 + 3 = 0

-1-(-3) = -1 + 3 = 2.

The values are -4, -2, 0, 2.

Now find the difference of these(2nd - 1st)

-2-(-4) = -2 + 4 = 2

0-(-2)= 0 + 2 = 2

2 - 0 = 2

Since all second differences gave 2 as their answer

Option B is your Quadratic Function!!!

Hope this helps!

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.