Solve the equation 6x^2 + 15x + 3= 2x^2 to the nearest tenth.

x = -0.2 and x = -3.5

Step-by-step explanation:

Combine like terms in the given equation, by subtracting 2x^2 from both sides:

6x^2 + 15x + 3 = 2x^2

-2x^2                = -2x^2

4x^2 + 15x + 3 = 0

This is a quadratic equation.  We'll find the two solutions using the quadratic equation

      -b ± √(b^2 - 4ac)

x =

                  2a

Here the coefficients of the quadratic are a = 4, b = 15 and c = 3.

Thus, the discriminant b^2 - 4ac is 15^2 - 4(4)(3), or +177

and from that we know we'll find two real, unequal roots.

                                -15 ± √177

The roots are:  x = , or x = -0.2 and x = -3.5

                                         8

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>