The Shredder, Inc. produces two types of paper shredders, home and office. The office model requires 4 hours to assembly and 6 finishing work units for finishing work, the home model requires 3 hours to
assemble and 6 finishing work units for finishing. The maximum number of assembly hours available is 72
per day, and the maximum number of finishing hours available is 132 per day.
Let 2 = the number of office model shredders produced per day and y = the number of home model
shredders produced per day.
Write the system of inequalities that represents the maximum number of shredders that can be produced in
one day.
NOTE: 4 inequalities are expected.
=<72
< 132ll

a

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!