Quadrilateral QRST is inscribed in the circle. Find the measurements of each of the angles in Quadrilateral QRST. Show your work. (x-6) (x+12) (x-4) ​

Given- O is the centre of a circle in which an equilateral ΔPQR has been inscribed.

To find out- ∠QOR=?

Solution- The points P, Q & R are on the circumference of the circle since ΔPQR has been inscribed in the circle. Now the chord QR subtends ∠QOR to the centre O and ∠QPR to the circumference at P.

∴ By rule, ∠QOR=2∠QPR(i).

Now PQR is an equilateral Δ. Each of its angle is 60

o

. i.e ∠QPR=60

o

.

So, from (i), ∠QOR=2∠QPR=2×60

o

=120

o

.

Ans- Option B.

solution

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl