Consider the relation y → 4 x−1 for the domain {3, 5, 7, 9} (a) Calculate the values for the range.

{ 11, 19, 27, 35 }

Step-by-step explanation:

To find the range substitute each value of x from the domain into the relation

x = 3 : y → 4(3) - 1 = 12 - 1 = 11

x = 5 : y → 4(5) - 1 = 20 - 1 = 19

x = 7 : y → 4(7) - 1 = 28 - 1 = 27

x = 9 : y → 4(9) - 1 = 36 - 1 = 35

range is { 11, 19, 27, 35 }

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft