A store manager can spend at most $1,000 a day for operating costs and payroll. It costs $100 each day to operate the store and $30 dollars a day for each employee. Use the following inequality to determine how many employees the manager can afford for the day, at MOST. 30x + 100 < 1000

A. X > 30

B. X > 33

C. X < 33

D. X < 30

x < 30

Step-by-step explanation:

Given the inequality expression that denotes the statement as;

30x+100 < 1000

Subtract 100 from both sides

30x + 100 - 100 <1000 - 100

30x < 900

Divide both sides by 30

30x/30 < 900/30

x < 30

Hence the required solution is x < 30

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

c

step-by-step explanation: