A circle in the standard (x, y) coordinate plane has center C(−1,2) and passes through A(2,6). Line
segment AB
___ is a diameter of this circle. What are the
coordinates of point B ?

Given:

Center of a circle is at point C(-1,2).

AB is the diameter of the circle.

Coordinates of the point A are A(2,6).

To find:

The coordinates of point B.

Solution:

Let the coordinates of point B are (a,b).

If AB is the diameter of the circle, then A and B are end points of diameter of the circle and the center C is the midpoint of AB.

Point C = Midpoint of AB

On comparing both sides, we get

Similarly,

Therefore, the coordinates of point B are (-4,-2).

⊂⊃⊂⊃ω

step-by-step explanation:

i hope this : )

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a