Subtract and simplify: 4yy2+10y+21−1y+3

4y−1(y+3)(y+7)

3y+7(y+3)(y+7)

3y−7(y+3)(y+7)

3y−3(y+3)(y+7)

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

0,0

step-by-step explanation:

answer: c

substitute in the values.

for a:

f(0) = 0 + 9

f(0) = 9

a is a solution.

for b:

f(7) = 14 + 9

f(7) = 23

b is a solution.

for c:

f (3) = 6 + 9

f(3) = 15

c is not a solution. it's supposed to be 14.

for d:

f(2) = 4 + 9

f(2)= 13

d is a solution.

the answer is $23.63