A line is parallel to 5x+2y-8-0 and has the same y-intercept as x+4y-12-0. Find the equation for the line in slope y-intercept form

y=(-5/2)x+3

Step-by-step explanation:

5x+2y-8=0

2y=-5x+8 Divide with 2

y=(-5/2)x+4

Slope is dy/dx

dy/dx=-5/2

x+4y-12=0 for x=0

4y-12=0

4y=12 Divide with 4

y=3 y-intercept

Line equation:

y = mx + b

This is called the slope-intercept form because "m" is the slope and "b" gives the y-intercept.

m-5/2 b=3

Euation for the your line:

y=(-5/2)x+3

p = 6s

step-by-step explanation: