What is an equation of the line that passes through the points (3, -3) and (6, -1)?​

Start by finding the slope using m = (y2 - y1)/(x2 - x1). Substituting in you get (-1 + 3)/(6 - 3). So m = 2/3

Next, use y - y1 = m(x - x1) and substitute any of the coordinates in: y + 3 = 2/3(x - 3). That gives you y + 3 = (2/3)x - 2. So tha final answer is y = (2/3)x -5

Aquadratic function is one of the form f(x)=ax2 + bx + c l, where a,b, and c are numbers with are not equal to zero.

The answer to your question is d 68%