1. If NK = 7 and KL = 15, find NL. 2. If m∠JMK = (8x – 13)° and m∠LMK = (4x + 19)°, find x.

NL = 13.26

x = 9.5

Step-by-step explanation:

Find the diagram attached

1) Given that NK = 7 and KL = 15

NL² =  KL² - NK²

NL²  = 15² -7²

NL²  = 176

NL  = 13.26

2) Given that m∠JMK = (8x – 13)° and m∠LMK = (4x + 19)°

From the  rhombus;

m<JML = 120 degrees

m∠JMK + m∠LMK = m∠JML

8x-13 + 4x +19 = 120

12x + 6 = 120

12x = 120-6

12x = 114

x = 114/12

x =  9.5

Hence the valle of x is 9.5

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12