What is the factorization of 49b2 − 81?

Step-by-step explanation:

The factorisation of 49b^2 - 81 is (7b - 9)(7b + 9). This is because 49 and 81 are the squares of 7 and 9 respectively, so these must be multiplied together. b^2 is b x b. Finally, it must be -9 and +9 to make -81, because when the signs are the same the result is a positive number

(7b - 9)(7b + 9)

Step-by-step explanation:

49b2 - 81

49 - 7 x 7

b2 - b x b

81 - 9 x 9

(a + b) (a - b) = a2 - b2

(7b - 9)(7b + 9)

3x^3-x^2+6x-9

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x