Find a equation of a line that is perpendicular to y=-4x+3 and passes through the point (4,-1).

Given:

The given equation is:

A line is perpendicular to the given line and passes through the point (4,-1).

To find:

The equation of required line.

Solution:

The slope intercept form of a line is:

Where, m is slope and b is y-intercept.

We have,

Here, the slope of the line is -4 and the y-intercept is 3.

Let the slope of required line be m.

We know that the product of slopes of two perpendicular lines is -1. So,

The slope of required line is and it passes through the point (4,-1). So, the equation of the line is:

Therefore, the equation of the required line is .

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!