Triangle J′K′L′ shown on the grid below is a dilation of triangle JKL using the origin as the center of dilation: Two triangles on a grid. First triangle has vertices J 4 and 6, K 2 and 4, and L 6 and 3. Image triangle has vertices J prime 8 and 12, K prime 4 and 8, L prime 12 and 6. Which scale factor was used to create triangle J′K′L′? 4 2 one quarter one half

64p2rh.e.x

step-by-step explanation:

the answer is y = 11.54

hope this : )

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180