A square pyramid. The square base has side lengths of 5 feet. The 4 triangular sides have a base of 5 feet and height of 6 feet. What is the surface area of a pyramid with a base area of 25 ft2 and lateral faces each with areas of 15 ft2?

85 ft^2

Step-by-step explanation:

Ok, the square base area is 5 x 5 = 25 square feet

the triangular sides have an area of (1/2)(5)(6) each, which is 15 square feet each, like you said.

To find the total surface area, you multiply the 15 square feet x 4 (there are 4 sides) and add the base.

15 x 4 = 60 + 25 = 85 square feet

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

no solution

step-by-step explanation:

there is not enough information in the problem to solve.