In a game of chess, a player can either win, draw or lose.
The probability that Vishi wins any
game of chess is 0.5
The probability that Vishi draws any
game of chess is 0.3
Vishi plays two games of chess.
Work out the probability that Vishi will
lose exactly one of the two games.
Pls answer fast

0.14

Step-by-step explanation:

If winning holds a probability of 0.5 and a draw holds a probability of 0.3, then that means that losing has a probability of 0.2 (1 - 0.5 - 0.7 = 0.2). Therefore, to find the probability of Vishi losing exactly one of the two games we need to multiply the probability of him losing one game by the probability of him winning or tying the second game like so...

0.2 * (0.5 + 0.3) = x

0.2 * 0.7 = x

0.14 = x

Finally, we can see that the probability of Vishi losing exactly one of the two games is 0.14

many reason,

step-by-step explanation: