What is the x-value of the vertex?

f (x) = (x + 2)^2 - 1

x-value of the vertex:

x-value of the vertex:-2

Solution given:

we have

f(x)=(x+2)²-1

y=x²+4x+3(I)

parameters of parabola are:

a=1

b=4

c=3

we have

vertex=-b/2a=-4/(2*1)=-2

substitute value of x in equation 1.

y=4-8+3= -1

So

vertex(-2,1)

Rewrite the equation in expanded form:

(X+2)^2 -1 = x^2 + 4x + 3

The parabola parameters are : a = 1, b = 4, c = 3

The x vertex is -b/2a = -4/2(1) = -2

Replace x with -2 in the expanded equation to solve for the y vertex:

Y = -1

The vertex is (-2,-1)

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step-by-step explanation: