The width of a rectangular parking lot is 53 ft less than its length. Determine the dimensions of the parking lot if it measures 250 ft diagonally.

The dimension of the lot is 201.28 ft by 148.28 ft

Step-by-step explanation:

Given;

diagonal of the parking lot, d = 250 ft

let the length of the parking lot = L

the width, W = L - 53

The diagonal of the lot, length of the lot, and width of the lot form a right triangle.

Apply Pythagoras theorem to determine the length, L

L²  +  W² = 250²

L²  + (L - 53)² = 250²

L²  +  L²  - 106L  +  2809 = 62,500

2L²  -  106L  + 2809  -  62,500 = 0

2L²  -  106L  - 59,691 = 0

this forms quadratic equation; a = 2, b = -106 and c = -59,691

The width, W = 201.28  -  53

                  W = 148.28 ft

so what is the problem what are they asking you to solve

step-by-step explanation:

so what is the problem what are they asking you to solve