Can somebody help me with this question

y = -⅓x + 7

Step-by-step explanation:

Given the two points that lie on the line (3, 6) and (-3, 8), we can find the equation without the grid by finding the slope (m) and y-intercept (b).

The equation would be written in the form of y = mx + b (slope-intercept form):

✔️Find m:

Slope (m) = change in y/change in x

Slope using (3, 6) and (-3, 8), would be:

Slope (m) = (8 - 6)/(-3 - 3) = 2/-6

m = -⅓

✔️Find b:

Substitute (x, y) = (3, 6) and m = -⅓ into y = mx + b to find b

6 = -⅓(3) + b

6 = -1 + b

6 + 1 = b

b = 7

✅Write the Equation:

Substitute m = -⅓ and b = 7 into y = mx + b

Thus,

y = -⅓x + 7

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}