Steps to turn quadratic equation in vertex form?

To change over a quadratic from y = ax2 + bx + c structure to vertex structure, y = a(x - h)2+ k, you utilize the way toward finishing the square. How about we see a model. Convert y = 2x2 - 4x + 5 into vertex structure, and express the vertex. Condition in y = ax2 + bx + c structure.

Step-by-step explanation:

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get

pentagon

step-by-step explanation:

the coordinates   a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.