One fair spinner (A-D) is spun and one fair dice (1-6) is rolled. What is the PROBABILITY that you will land on a B ANDan EVEN number? SHOW YOUR WORK! Use the sample space from question 8 to assist you! Write your answer in SIMPLIFIED FRACTION form.

Fair spinner contains: A, B, C, D
fair dice contains: 1, 2, 3, 4, 5, 6

There are 10 outcomes in total
1/10 chance to land on B and 3/10 chance to land on and even number.
If you add those it would be
1/10 + 3/10 = 4/10
4/10 = 2/5

The probability of landing on B and an even number is 2/5.

(I just started learning probabilities so please correct me if im wrong ;v;)

Answer- 1/12

Explanation- You can spin A,B,C,D, and you can roll 1,2,3,4,5, or 6.

Because the question is asking to roll an even number 2,4,6 and B, you have to multiply the probabilities of those happening.

Rolling an even number is 1/3 (2,4,6 out of 6), and rolling a B is 1/4(there is only one B out of A,B,C,D.)

If you multiply the two you get 1/12.

Hope that helps!

It should be c i think.

If your asking how much altogether for 12 performance the answer will be 98,496.