Renee has dimes and quarters in her wallet that total $1.60. She has 2 more dimes than quarters. How many of each coin does Renee have?

Given:

Renee has dimes and quarters in her wallet that total $1.60.

She has 2 more dimes than quarters.

To find:

The number of each type of coins.

Solution:

Let x be the number of dimes and y be the number of quarters.

She has 2 more dimes than quarters. So,

           ...(i)

We know that,

1 dime = $0.10

1 quarter = $0.25

Renee has dimes and quarters in her wallet that total $1.60. So,

             ...(ii)

From (i) and (ii), we get

Divide both sides by 0.35.

Substituting in (i), we get

Therefore, the number of dimes is 6 and the number of quarters is 4.

$32,660

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet