This problem has questions about UCSC ID numbers. UCSC ID numbersall have 7 digits from 0 to 9. We will assume that all digits can be 0 through 9. Becareful! There are subtleties lurking here. a. How many UCSC ID numbers have digits that sum to 9?
b. How many UCSC ID numbers have digits that sum to 17?
c. What size class must have at least 3 students whose UCSC ID numbers sum to the same number?
d. What is the probability that a randomly selected UCSC ID sums to more than 17?

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.

8/k

step-by-step explanation:

b because it contains 40% of the possible results from the random list.  

0,1,2,3 v 4,5,6,7,8,9  

4 integers to 6 integers  

40% success vs 60% fail

step-by-step explanation: