Explain how to determine the zeros of f(x)= (x+3)(x-2)(x-6)

The zeros of f(x)  are -3, 2 , 6

Step-by-step explanation:

f(x) is a polynomial of degree 3.

If the polynomial is not factorized we will either factorize to find the zero or use trial and error method.

Since the f(x) in the question is in the factorized form. we will have to equate each factor to zero.

f(x) = (x+3)(x-2)(x-6)

x + 3 = 0 => x = -3

x - 2 = 0 =>  x = 2

x - 6 = 0 => x = 6

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

answer: -1

step-by-step explanation: