Determine and state the vertex of f(x) = x2 - 2x - 8 using the method of completing the square

vertex = (1, - 9 )

Step-by-step explanation:

The equation of a parabola in vertex form is

f(x) = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

f(x) = x² - 2x - 8

To complete the square

add/ subtract ( half the coefficient of the x- term )² to x² - 2x

f(x) = x² + 2(- 1)x + 1 - 1 - 8

     = (x - 1)² - 9 ← in vertex form

with vertex = (1, - 9 )

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -

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step-by-step explanation:

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