Un circuito RL en serie, como se muestra en la figura, tiene una autoinductancia de L = 0.5 henrys, un potenciómetro (resistencia variable con el tiempo) de R = e∧-t∧2 ohms y una fuente de voltaje definida por la expresión E(t) = ⟦t + 1⟧ (sin2 ⁄ (t) + 2) volts. Si el interruptor se cierra en el instante t = 0, la corriente satisface la
ecuación diferencial de primer orden:

Determine el valor de la corriente para 0 ≤ t < 2 segundos,
mediante el método de Euler y el método de Heun, con h = 0.1.
Realice una tabla donde se muestren los valores de corriente
solicitados.

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

image for option 4

step-by-step explanation:

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i don't know

step-by-step explanation: