What is the approximate sector area of a sector defined by minor arc CB?

d. 7.5 cm²

Step-by-step explanation:

Area of sector = central angel/360 × πr²

Central angle = 180° - 84° = 96° (supplementary angles)

BA = radius (r) = ½(6) = 3 cm

Plug in the values

Area of sector = 96/360 × π*3²

= 7.53982238

= 7.5 cm² (nearest tenth)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

i believe the correct answer is option 4.principalities were small territories that were run by russian rulers.

which statement correctly defines principalities in northern asia in the 1200s? principalities were small territories that were run by russian rulers.

hope i could ! : )