Find the equation of a line perpendicular to 2x-y+6=0 through the point (0, -2)

Step-by-step explanation:

Let's first rearrange so it's easier to look at: y = 2x +6

To find the perpendicular slope you need to find the negative reciprocal of m so flip and change the sign:

m= -1/2

Next plug in the point (0, -2) into the point-slope equation of a line:

y-(-2) = -1/2 (x-0)

y + 2 = -1/2x

y = -1/2x - 2

Therefore the equation is y = -1/2x - 2

no this is a nonlinear negative

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !