Mathematics, 11.06.2021 01:40 885122bah

Two-step equations - integers Solve each equation. (Will give brainlest, show your work)

Question 1: Solve -3 + v/5 = 0

Question 2: Solve 1 - 7b = -20

Question 3: Solve -k - 5 = 0

Question 4: Solve -1 + 8a = 129

Answers: 2

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Answers

Answer from: viv1302

Question 1. -3 + v5 = 0
Work : -3 + 5v = 0
5v = 3 ( divide )
answer v = 3/5

Question 2. 1 - 7B = -20
work : -7b = -20 - 1
-7b = -21 ( divide )
answer b = 3

question 3 : -k - 5 = 0
work : -k = 5
answer : k = - 5

Question 4 : -1 + 8a = 129
work : 8a = 129 + 1
8a = 130 (divide )
answer a = 65/4

Answer from: 10crank78

Question 1. -3 + v5 = 0

Work : -3 + 5v = 0

5v = 3 ( divide )

answer v = 3/5

Question 2. 1 - 7B = -20

work : -7b = -20 - 1

-7b = -21 ( divide )

answer b = 3

question 3 : -k - 5 = 0

work : -k = 5

answer : k = - 5

Question 4 : -1 + 8a = 129

work : 8a = 129 + 1

8a = 130 (divide )

answer a = 65/4

Step-by-step explanation:

Answer from: Quest

step-by-step explanation:

Answer from: Quest

(2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

step-by-step explanation:

simplify the following:

x/x^2 + 3 x + 2 - (x (x + 1))/(x + 2)

combine powers. x/x^2 = x^(1 - 2):

x^(1 - 2) + 3 x + 2 - (x (x + 1))/(x + 2)

1 - 2 = -1:

x^(-1) + 3 x + 2 - (x (x + 1))/(x + 2)

put each term in 1/x + 3 x + 2 - (x (x + 1))/(x + 2) over the common denominator x (x + 2): 1/x + 3 x + 2 - (x (x + 1))/(x + 2) = (x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)):

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2))

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)) = ((x + 2) + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2)):

(2 + x + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

3 x^2 (x + 2) = 3 x^3 + 6 x^2:

(2 + x + 3 x^3 + 6 x^2 + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

2 x (x + 2) = 2 x^2 + 4 x:

(2 + x + 6 x^2 + 3 x^3 + 2 x^2 + 4 x - x^2 (x + 1))/(x (x + 2))

-x^2 (x + 1) = -x^2 - x^3:

(-x^2 - x^3 + 3 x^3 + 6 x^2 + 2 x^2 + 4 x + x + 2)/(x (x + 2))

grouping like terms, 3 x^3 - x^3 + 6 x^2 + 2 x^2 - x^2 + 4 x + x + 2 = (3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2:

((3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

3 x^3 - x^3 = 2 x^3:

(2 x^3 + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

6 x^2 + 2 x^2 - x^2 = 7 x^2:

(2 x^3 + 7 x^2 + (x + 4 x) + 2)/(x (x + 2))

x + 4 x = 5 x:

answer: (2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

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Two-step equations - integers Solve each equation. (Will give brainlest, show your work)

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