Determine the location and absolute maximum and absolute minimum for the given function f(x)=(_x+2)^4 where 0

the minimum is 0 and the maximum is 16.

Step-by-step explanation:

For a function f(x), the maximum is defined as:

f(xₐ)

such that:

f(xₐ) ≥ f(x) for every value of x in the domain.

And the minimum is:

f(xₙ)

Such that:

f(xₙ) ≤ f(x)

for every value of x.

Now, in this case we have the function:

f(x) = (-x + 2)^4 in the range  0 < x < 3

First, let's analyze our function.

We can see that the exponent is even, then:

f(x) = (-x + 2)^4

Can be equal to zero or larger than zero.

Then the minimum will be f(x) = 0

To find this, we need to find the value of x such that:

-x +2 = 0

2 = x

Then the minimum is:

f(2) = (-2 + 2)^4 = 0

For the maximum, we can just play with the other values in the range and see which one gives the larger value of f(x).

Again, because f(x) =  (-x + 2)^4 , the maximum will be at the value of x such that:

|-x + 2| is maximized.

As we have a negative sign multiplying x, the smaller value in the range:

x = 0

is the one that maximizes that:

|-0 + 2| = |2| = 2

Evaluating f(x) in x = 0 we get:

f(0) = (0 + 2)^4 = 16

Then the minimum is 0 and the maximum is 16.

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

i think asking google will you get the answer to that question