The perimeter of the rectangle below is 130 units. Find the value of z

9 =z

Step-by-step explanation:

The perimeter of a rectangle is

P = 2(l+w) where l is the length and w is the width

P = 2(3z+2+ 4z)

Combine like terms

P = 2(7z+2)

Substitute in the perimeter

130 = 2( 7z+2)

Divide each side by 2

130/2 = 2/2 ( 7z+2)

65 = 7z+2

Subtract 2 from each side

65-2 = 7z+2-2

63 = 7z

Divide by 7

63/7 = 7z/7

9 =z

ok i think its 32.5

Step-by-step explanation:

3z+2 (which u need to subtract) to get 1z

then 1zx4x=4x

130/4z=32.5

hope i helped

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)