A baseball is thrown straight up in the air with an initial velocity of 128 feet per second from a point
exactly 4 feet off the ground.
Write the function for the height of this object at any
time (t seconds)

Step-by-step explanation:

where

h(t) is the height of the ball after a certain amount of time has gone by,

-16t² is the pull of gravity in ft/s/s,

v₀t is the initial upwards velocity, and

h₀ is the height from which the ball was initially thrown. Our equation is then, filling in the info in the correct places:

where 128 is the given initial velocity and 4 is the number of feet from which the ball was initially launched.

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.