Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution set of this problem?
0 (-0, -21)
O (-0, -21]
o [-21, +00)
O (21, +00)

5 × (x + 27) ≥ 6 × (x + 26).

Step-by-step explanation:

the least common denominator is 40

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine