1, Find the interior angle of a regular polygon with 20 sides. What is the size of exterior angle? 2, Calculate the
(I) exterior angle
(ii) the number of sides of a regular polygon with an interior angle of
(a) 60° (b) 72° (c) 165°​

Step-by-step explanation:

1) (20 -2) * 180 = 3240 (sum of the inner angles)

3240 : 20 = 162 degrees

2)  (I) 180 - 162 = 18 degrees

(ii)

a = 3 (it is an equilateral triangle)

b = 5 (it is a pentagon)

c = 24

1. 180(n-2) gives you the angle sum

devide by n to get the value of one interior angle

n are the number of sides, or corners

180(20-2)/20 = 162° is the interior angle.

the exterior angle is just 360°-162° = 198°

2i) seems to be included in 1), pls clarify if that's not the case.

remember

180(n-2)/n = int.angle

let's do this with (a) 60°

180(n-2)/n = 60

(180n-360)/n = 60 |*n

180n-360 = 60n |-180n

-360 = -120n |/(-120)

3 = n

2iia) 3 sides / triangle

2iib) 5 sides / pentagon

2iic) 24 sides

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.