I'm kinda lost here, what do I do when the quadrant is given? CanI have some of these solved at least with steps?

See Explaination

Step-by-step explanation:

According To Question

(Diagram, Please Find In Attachment)

Question 38 . Cos ∅ = 12/13   ∅ in Quadrant-4(Where only Cos & Sec are Positive all other Functions Are Negative in this Quadrant)

Now ∅ Represent a Right Angle Triangle with Base=12 Perpendicular=5 & Hypothenese=13

Sin∅ = -5/13 , Cosec∅=-13/5 , Tan∅=-5/12 , Cot∅=-12/5 & Sec∅=13/12

Question 39 . SinX=-3/4   X Lies in Quadrant-3(Where only Tan & Cot are Positive all other Functions Are Negative in this Quadrant)

Find By Using Basic Formulas

↔ Put Value of Sin∅=-3/4

We get CosX= ± (but X Lies in Quadrant-3 Where Cosine Is Negative , So Neglect CosX= +)

So CosX= - ...... now you get the point . All Questions Will Solve like This .

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

22

step-by-step explanation: