Complete the square to rewrite y=x2 - 6x + 2 in vertex form. Then state whether the vertex is a maximum or a minimum and give its coordinates. A. Maximum at (-3, -7)

B. Maximum at (3,-7)

C. Minimum at (3, -7)

D. Minimum at (-3, -7) ​

C) Minimum at (3,-7)

Step-by-step explanation:

Because the parabola opens upward, the vertex is the minimum of the function. Therefore, the vertex is the minimum at (3,-7).

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204