Hi can you answer this question thank you​

9514 1404 393

  2 < x < 24.937

Step-by-step explanation:

Conceptually, the values of x are allowed to be between those that make angle ABC one of zero measure and that make angle ABD a straight angle.

That is ...

  0 < 2x-4 < 180 -86

  4 < 2x < 98

  2 < x < 49

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However, some study of this geometry convinces us that the largest that angle ABC can be is one that makes ∆ABC isosceles. In that case, AB = CB = DB, and B is the center of the circle through points A, C, and D. Trigonometry can be used to find the value of x in that case.

The radius CB of circle B must be such that the bisector of angle CBD intersects the midpoint of CD:

  CB·sin(86°/2) = 14/2

Similarly, the bisector of angle ABC will meet the midpoint of AC:

  CB·sin((2x -4)°/2) = 8/2

Equating expressions for CB gives ...

  7/sin(43°) = 4/sin((x-2)°)

  (x -2)° = arcsin((4/7)sin(43°))

  x° = 2° +arcsin(4/7·sin(43°))

  x ≈ 24.937

So, a revised upper limit on x puts the range of possible values as ...

  2 < x < 24.937

step-by-step explanation: