PLEASE HELP DONT SKIP I NEED YOU Find the number of different outfits that can be made from 3 sweaters, 4 shirts, and 6 pants. Then find the probability of selecting a particular sweater, shirt, and pants outfit.

outcome -

Probability (as a fraction) -

72 outfits possible,

1/72 chance of selecting a particular outfit

Step-by-step explanation:

For each of the 3 sweaters, there are 4 shirts to choose from, and for each of those 4 shirts, there are 6 pants to choose from. Therefore, there are totally outfits to choose from (order is fixed and therefore negligible). A specific outfit would represent 1 of these 72 outfits. Therefore, the probability of selecting a particular outfit is

answer: f = 32.2m

step-by-step explanation: that is the answer

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0