3 JK, KL, and IJ are all tangent to o (not drawn to scale). JA = 8, AL = 11, and
CK = 10. Find the perimeter of AJKL.

Step-by-step explanation:

The image if the circle and triangle can be found online

Given

Required

The perimeter of JKL

Since the mid-points of the tangents are A, B and C respectively.

Where

So:

Where

So:

So, the perimeter (P) is:

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb