Solve the system of equations: y=2x+1. y=x^2+2x-8

(- 3, - 5 ) , (3, 7 )

Step-by-step explanation:

Given the 2 equations

y = 2x + 1 → (1)

y = x² + 2x - 8 → (2)

Substitute y = x² + 2x - 8 into (1)

x² + 2x - 8 = 2x + 1 ( subtract 2x + 1 from both sides )

x² - 9 = 0 ( add 9 to both sides )

x² = 9 ( take the square root of both sides )

x = ± = ± 3

Substitute these values into (1) for corresponding values of y

x = - 3 : y = 2(- 3) + 1 = - 6 + 1 = - 5 ⇒ (- 3, - 5 )

x = 3 : y = 2(3) + 1 = 6 + 1 = 7 ⇒ (3, 7 )

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

the square root of what number? if you add that, then someone will probably answer the question.