1. My number has two digits 2. I am greater than 30
3. I am less than 90
4. My second digit is greater than 3
5. My first digit is divisible by 2
6. Both of my digits add up to either 11 or 12
7. I am the smallest number of
the four numbers that are left.

47

Step-by-step explanation:

1. #2 and #3 reveal that it must be between 31 to 89

2. #4 and #5 reveals that the answer is one of these numbers:

44, 45, 46, 47, 48, 49

64, 65, 66, 67, 68, 69

84, 85, 86, 87, 88, 89

This is because only 4, 6, and 8 are divisible by 2

3. You must add up all the numbers to see which ones add up to either 11 or 12.

4 + 7 = 11

4 + 8 = 12

6 + 5 = 11

6 + 6 = 12

8 + 4 = 12

This means that these are the following numbers: 47, 48, 65, 66, 84

4. #7 says that you must find the smallest number. The smallest number left is 47.

its c or d   take a lucky guess my dude