Mathematics, 15.06.2021 14:00 madisontrosclair2
Cho ánh xạ tuyến tính f : R^3 → R^3 và hai cơ sở của R^3 :
B ={b1=(1,3,3),b2=(-7,6,5),b3=(1,2,2) }
C= {c1=(2,-4,3),c2=(-5,-1,-5),c3=(1,0, 1)}
Biết:
f b(1 ) ( -5,6,4) =
f b(2 ) ( -8,5,2) =
f b( 2) ( -9, -2, -5) =
a. Tìm ma trận A=[F]e3'= , từ đó suy ra biểu thức của f(x1,x2,x3)
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Cho ánh xạ tuyến tính f : R^3 → R^3 và hai cơ sở của R^3 :
B ={b1=(1,3,3),b2=(-7,6,5),b3=(1,2,2) }<...
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