Write an equation in point-slope form for the line through the given point with the given slope. (8, –3); m = -1/4

y+3 = -1/4(x-8)

Step-by-step explanation:

Point slope form is y-y1 = m(x-x1)  where m is the slope and (x1-y1) is a point on the line

(y- -3) =-1/4(x-8)

y+3 = -1/4(x-8)

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

its   c, f, a

step-by-step explanation: