F (x) =x^2-6x+4 how do i find the vertex ?

(3, -5)

Step-by-step explanation:

So, there are three steps in finding the vertex.

We need to first find a, b and c. a is the x^2 coefficent, b is the x cofficent, and c is the number value. In this case:

a=1, b=-6, and c=4

To find the x value of the vertex, plug in a and b into the formula:

-b/2a = x coord of vertex:

-*-6/2*1

=

6/2

=

3

So the x coordinates of the vertex is 3.

To find the y cooridnates, plug in 3 into the orginal equation:

=

=

So -5 is the y coordinates of the vertex.

(3, -5)

Hope this helps!

Going over steps:

Step 1 - Find values a b and c: a=x^2 coefficent. b=x coefficent. c=number

Step 2 - Plug in a and b into -b/2a

Step 3 - Plug in x into equation

18

step-by-step explanation:

ik this stuph and i am smart donkey

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?