I need help finding the distince.​

guessing that the area of the inner rectangle is 10m²

and the other rectangle is 16m*10m= 160m²

we can say that

(16-x) * (10-x) = 10

for the area of the inner rectangle

let's calculate the lefthand side of the equation

160 - 16x -10x + x² = 10

160 -26x +x² = 10

subtract 10 on both sides

150 -26x +x² = 0

rearrange

x² -26x + 150 = 0

looks like something we can throw the pq formula on to solve for x

with p = -26 and q = 150

we need to interpret this solutions

but to be sure on this, I need the unreadable text of the photographed problem

answer:

1.14285714286

step-by-step explanation:

divide 40 into 35 and you will get your answer

1. 180°. the sum of the interior angles of a triangle is 180°, for the equilateral triangle that it has three equals side is 60°+60°+60°=180°.

2. 60°. each interior angle of a equilateral triangle is 60°

3. 120°. the measure of ∠m is 120°, the sum of the angles ∠m and ∠n is equal to 180°. so, in order to find the measure of ∠m, we have ∠m+∠n=180° > ∠m=180°-∠n > ∠m=180°-60°=120°.

4. 360°. the sum of the exterior angles of an equilateral triangle is ∠m+∠r+∠x=120°+120°+120°=360°. the exterior angles of any triangle always add 360°.