Assume that the tunnel in Exercise 3.132 is observed during ten two-minute intervals, thus giving ten independent observations Y1, Y2,..., Y10, on the Poisson random variable. Find the probability that Y > 3 during at least one of the ten two-minute intervals

hello the exercise is missing from your question below is the missing exercise for reference

0.1745

Step-by-step explanation:

Determine  P ( Y > 3 )

Given that y follows Poisson distribution with mean

P( Y = y ) =

assuming that yi represents number of autos that will enter the tunnel and

also let A represent Y > 3 at one of the ten two-minute interval

step 1 : hence finding  P(A )

= P(Y > 3 ) = 1 - P( Y≤ 3 )

= 1 - [

= 0.018988

since the ten observations are independent

P(X≥ 1 ) = 1 - P( X = 0 )

            = 1 -    * (0.018988)^0 ( 1 - 0.018988)^10-0

            = 1 - 0.8255 = 0.1745

b

step-by-step explanation:

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.