A bag contains exactly 50 coins. The coins are either worth 10 cents, 20 cents or 50 cents and there is Atleast one of each. The total value of the coins is $10. How many different ways can this occur?

This can happen in two ways:

1) 42 20-cent coins, 6 10-cent coins and 2 50-cent coins.

2) 30 10-cent coins, 10 20-cent coins and 10 50-cent coins.

Step-by-step explanation:

Given that a bag contains exactly 50 coins, and the coins are either worth 10 cents, 20 cents or 50 cents and there is at least one of each, and the total value of the coins is $ 10, to determine how many different ways can this occur, the following calculation must be performed:

48 x 0.5 + 1 x 0.2 + 1 x 0.1 = 24.30

48 x 0.1 + 1 x 0.2 + 1 x 0.5 = 5.5

48 x 0.2 + 1 x 0.1 + 1 x 0.5 = 10.3

45 x 0.2 + 4 x 0.1 + 1 x 0.5 = 9.9

44 x 0.2 + 5 x 0.1 + 1 x 0.5 = 9.8

42 x 0.2 + 6 x 0.1 + 2 x 0.5 = 10

30 x 0.1 + 10 x 0.2 + 10 x 0.5 = 10

Therefore, this can happen in two ways:

1) 42 20-cent coins, 6 10-cent coins and 2 50-cent coins.

2) 30 10-cent coins, 10 20-cent coins and 10 50-cent coins.

step-by-step explanation:

divide, then simplify your answer.

1. make -15.66 ÷   5.8 a fraction. then divide.

2. simplify.  

3. final answer.  

answer by yourhope:

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